6(x-2)/3=4(x+1)/8

Solution for 6(x-2)/3=4(x+1)/8 equation:

6(x-2)/3=4(x+1)/8

We move all terms to the left:

6(x-2)/3-(4(x+1)/8)=0

We calculate fractions


6x/()+(-(4(x+1)*3)/()=0


We calculate terms in parentheses: +(-(4(x+1)*3)/(), so:

-(4(x+1)*3)/(

We multiply all the terms by the denominator


-(4(x+1)*3)


We calculate terms in parentheses: -(4(x+1)*3), so:

4(x+1)*3

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)


We get rid of parentheses

-12x-12

Back to the equation:

+(-12x-12)


We get rid of parentheses

6x/()-12x-12=0

We multiply all the terms by the denominator


6x-12x*()-12*()=0

We add all the numbers together, and all the variables

6x-12x*()=0