6(x-2)/4=3(x+3)/7

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Solution for 6(x-2)/4=3(x+3)/7 equation: 



6(x-2)/4=3(x+3)/7

We move all terms to the left:

6(x-2)/4-(3(x+3)/7)=0

We calculate fractions


6x/()+(-(3(x+3)*4)/()=0



We calculate terms in parentheses: +(-(3(x+3)*4)/(), so:

-(3(x+3)*4)/(

We multiply all the terms by the denominator


-(3(x+3)*4)



We calculate terms in parentheses: -(3(x+3)*4), so:

3(x+3)*4

We multiply parentheses

12x+36

Back to the equation:

-(12x+36)



We get rid of parentheses

-12x-36

Back to the equation:

+(-12x-36)



We get rid of parentheses

6x/()-12x-36=0

We multiply all the terms by the denominator


6x-12x*()-36*()=0

We add all the numbers together, and all the variables

6x-12x*()=0

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