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6(x-2)=(3x-1)
We move all terms to the left:
6(x-2)-((3x-1))=0
We multiply parentheses
6x-((3x-1))-12=0
We calculate terms in parentheses: -((3x-1)), so:We get rid of parentheses
(3x-1)
We get rid of parentheses
3x-1
Back to the equation:
-(3x-1)
6x-3x+1-12=0
We add all the numbers together, and all the variables
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3
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