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6(x-2)=3x+2(x-1)
We move all terms to the left:
6(x-2)-(3x+2(x-1))=0
We multiply parentheses
6x-(3x+2(x-1))-12=0
We calculate terms in parentheses: -(3x+2(x-1)), so:We get rid of parentheses
3x+2(x-1)
We multiply parentheses
3x+2x-2
We add all the numbers together, and all the variables
5x-2
Back to the equation:
-(5x-2)
6x-5x+2-12=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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