6(x-2)=4(x-2+3x)+7(x-1)

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Solution for 6(x-2)=4(x-2+3x)+7(x-1) equation: 



6(x-2)=4(x-2+3x)+7(x-1)

We move all terms to the left:

6(x-2)-(4(x-2+3x)+7(x-1))=0

We add all the numbers together, and all the variables

6(x-2)-(4(4x-2)+7(x-1))=0

We multiply parentheses

6x-(4(4x-2)+7(x-1))-12=0



We calculate terms in parentheses: -(4(4x-2)+7(x-1)), so:

4(4x-2)+7(x-1)

We multiply parentheses

16x+7x-8-7

We add all the numbers together, and all the variables

23x-15

Back to the equation:

-(23x-15)



We get rid of parentheses

6x-23x+15-12=0

We add all the numbers together, and all the variables

-17x+3=0

We move all terms containing x to the left, all other terms to the right

-17x=-3

x=-3/-17

x=3/17

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