6(x-3)+(3x-7)=12(x+2)

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Solution for 6(x-3)+(3x-7)=12(x+2) equation: 



6(x-3)+(3x-7)=12(x+2)

We move all terms to the left:

6(x-3)+(3x-7)-(12(x+2))=0

We multiply parentheses

6x+(3x-7)-(12(x+2))-18=0

We get rid of parentheses

6x+3x-(12(x+2))-7-18=0



We calculate terms in parentheses: -(12(x+2)), so:

12(x+2)

We multiply parentheses

12x+24

Back to the equation:

-(12x+24)



We add all the numbers together, and all the variables

9x-(12x+24)-25=0

We get rid of parentheses

9x-12x-24-25=0

We add all the numbers together, and all the variables

-3x-49=0

We move all terms containing x to the left, all other terms to the right

-3x=49

x=49/-3

x=-16+1/3

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