6(x-3)+10=2(3x+4)

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Solution for 6(x-3)+10=2(3x+4) equation:


Simplifying
6(x + -3) + 10 = 2(3x + 4)

Reorder the terms:
6(-3 + x) + 10 = 2(3x + 4)
(-3 * 6 + x * 6) + 10 = 2(3x + 4)
(-18 + 6x) + 10 = 2(3x + 4)

Reorder the terms:
-18 + 10 + 6x = 2(3x + 4)

Combine like terms: -18 + 10 = -8
-8 + 6x = 2(3x + 4)

Reorder the terms:
-8 + 6x = 2(4 + 3x)
-8 + 6x = (4 * 2 + 3x * 2)
-8 + 6x = (8 + 6x)

Add '-6x' to each side of the equation.
-8 + 6x + -6x = 8 + 6x + -6x

Combine like terms: 6x + -6x = 0
-8 + 0 = 8 + 6x + -6x
-8 = 8 + 6x + -6x

Combine like terms: 6x + -6x = 0
-8 = 8 + 0
-8 = 8

Solving
-8 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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