6(x-3)+10=2(4x-10)

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Solution for 6(x-3)+10=2(4x-10) equation: 



6(x-3)+10=2(4x-10)

We move all terms to the left:

6(x-3)+10-(2(4x-10))=0

We multiply parentheses

6x-(2(4x-10))-18+10=0



We calculate terms in parentheses: -(2(4x-10)), so:

2(4x-10)

We multiply parentheses

8x-20

Back to the equation:

-(8x-20)



We add all the numbers together, and all the variables

6x-(8x-20)-8=0

We get rid of parentheses

6x-8x+20-8=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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