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6(x-3)+3x=21-3(x+9)
We move all terms to the left:
6(x-3)+3x-(21-3(x+9))=0
We add all the numbers together, and all the variables
3x+6(x-3)-(21-3(x+9))=0
We multiply parentheses
3x+6x-(21-3(x+9))-18=0
We calculate terms in parentheses: -(21-3(x+9)), so:We add all the numbers together, and all the variables
21-3(x+9)
determiningTheFunctionDomain -3(x+9)+21
We multiply parentheses
-3x-27+21
We add all the numbers together, and all the variables
-3x-6
Back to the equation:
-(-3x-6)
9x-(-3x-6)-18=0
We get rid of parentheses
9x+3x+6-18=0
We add all the numbers together, and all the variables
12x-12=0
We move all terms containing x to the left, all other terms to the right
12x=12
x=12/12
x=1
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