6(x-3)+4(x+2)=17(x-3)-2(x+2)

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Solution for 6(x-3)+4(x+2)=17(x-3)-2(x+2) equation: 



6(x-3)+4(x+2)=17(x-3)-2(x+2)

We move all terms to the left:

6(x-3)+4(x+2)-(17(x-3)-2(x+2))=0

We multiply parentheses

6x+4x-(17(x-3)-2(x+2))-18+8=0



We calculate terms in parentheses: -(17(x-3)-2(x+2)), so:

17(x-3)-2(x+2)

We multiply parentheses

17x-2x-51-4

We add all the numbers together, and all the variables

15x-55

Back to the equation:

-(15x-55)



We add all the numbers together, and all the variables

10x-(15x-55)-10=0

We get rid of parentheses

10x-15x+55-10=0

We add all the numbers together, and all the variables

-5x+45=0

We move all terms containing x to the left, all other terms to the right

-5x=-45

x=-45/-5

x=+9

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