6(x-3)+4=10+4(2x-1)

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Solution for 6(x-3)+4=10+4(2x-1) equation: 



6(x-3)+4=10+4(2x-1)

We move all terms to the left:

6(x-3)+4-(10+4(2x-1))=0

We multiply parentheses

6x-(10+4(2x-1))-18+4=0



We calculate terms in parentheses: -(10+4(2x-1)), so:

10+4(2x-1)

determiningTheFunctionDomain
4(2x-1)+10

We multiply parentheses

8x-4+10

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

6x-(8x+6)-14=0

We get rid of parentheses

6x-8x-6-14=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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