6(x-3)+4=10+4=(2x-1)

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Solution for 6(x-3)+4=10+4=(2x-1) equation: 



6(x-3)+4=10+4=(2x-1)

We move all terms to the left:

6(x-3)+4-(10+4)=0

We add all the numbers together, and all the variables

6(x-3)+4-14=0

We add all the numbers together, and all the variables

6(x-3)-10=0

We multiply parentheses

6x-18-10=0

We add all the numbers together, and all the variables

6x-28=0

We move all terms containing x to the left, all other terms to the right

6x=28

x=28/6

x=4+2/3

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