6(x-3)+4x=72

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Solution for 6(x-3)+4x=72 equation: 



6(x-3)+4x=72

We move all terms to the left:

6(x-3)+4x-(72)=0

We add all the numbers together, and all the variables

4x+6(x-3)-72=0

We multiply parentheses

4x+6x-18-72=0

We add all the numbers together, and all the variables

10x-90=0

We move all terms containing x to the left, all other terms to the right

10x=90

x=90/10

x=9

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