6(x-3)+7=7x-2(1+5x)

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Solution for 6(x-3)+7=7x-2(1+5x) equation: 



6(x-3)+7=7x-2(1+5x)

We move all terms to the left:

6(x-3)+7-(7x-2(1+5x))=0

We add all the numbers together, and all the variables

6(x-3)-(7x-2(5x+1))+7=0

We multiply parentheses

6x-(7x-2(5x+1))-18+7=0



We calculate terms in parentheses: -(7x-2(5x+1)), so:

7x-2(5x+1)

We multiply parentheses

7x-10x-2

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

6x-(-3x-2)-11=0

We get rid of parentheses

6x+3x+2-11=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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