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6(x-3)+8=2x+4(-2+x)
We move all terms to the left:
6(x-3)+8-(2x+4(-2+x))=0
We add all the numbers together, and all the variables
6(x-3)-(2x+4(x-2))+8=0
We multiply parentheses
6x-(2x+4(x-2))-18+8=0
We calculate terms in parentheses: -(2x+4(x-2)), so:We add all the numbers together, and all the variables
2x+4(x-2)
We multiply parentheses
2x+4x-8
We add all the numbers together, and all the variables
6x-8
Back to the equation:
-(6x-8)
6x-(6x-8)-10=0
We get rid of parentheses
6x-6x+8-10=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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