6(x-3)+x=4(2x+1)-22

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Solution for 6(x-3)+x=4(2x+1)-22 equation: 



6(x-3)+x=4(2x+1)-22

We move all terms to the left:

6(x-3)+x-(4(2x+1)-22)=0

We add all the numbers together, and all the variables

x+6(x-3)-(4(2x+1)-22)=0

We multiply parentheses

x+6x-(4(2x+1)-22)-18=0



We calculate terms in parentheses: -(4(2x+1)-22), so:

4(2x+1)-22

We multiply parentheses

8x+4-22

We add all the numbers together, and all the variables

8x-18

Back to the equation:

-(8x-18)



We add all the numbers together, and all the variables

7x-(8x-18)-18=0

We get rid of parentheses

7x-8x+18-18=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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