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6(x-3)-(6-2x)=2(x+2)-5(5-x)
We move all terms to the left:
6(x-3)-(6-2x)-(2(x+2)-5(5-x))=0
We add all the numbers together, and all the variables
6(x-3)-(-2x+6)-(2(x+2)-5(-1x+5))=0
We multiply parentheses
6x-(-2x+6)-(2(x+2)-5(-1x+5))-18=0
We get rid of parentheses
6x+2x-(2(x+2)-5(-1x+5))-6-18=0
We calculate terms in parentheses: -(2(x+2)-5(-1x+5)), so:We add all the numbers together, and all the variables
2(x+2)-5(-1x+5)
We multiply parentheses
2x+5x+4-25
We add all the numbers together, and all the variables
7x-21
Back to the equation:
-(7x-21)
8x-(7x-21)-24=0
We get rid of parentheses
8x-7x+21-24=0
We add all the numbers together, and all the variables
x-3=0
We move all terms containing x to the left, all other terms to the right
x=3
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