6(x-3)-(x+2)x=1

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Solution for 6(x-3)-(x+2)x=1 equation: 



6(x-3)-(x+2)x=1

We move all terms to the left:

6(x-3)-(x+2)x-(1)=0

We multiply parentheses

-x^2+6x-2x-18-1=0

We add all the numbers together, and all the variables

-1x^2+4x-19=0

a = -1; b = 4; c = -19;
Δ = b2-4ac
Δ = 42-4·(-1)·(-19)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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