6(x-3)-1=2(x+5)

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Solution for 6(x-3)-1=2(x+5) equation: 



6(x-3)-1=2(x+5)

We move all terms to the left:

6(x-3)-1-(2(x+5))=0

We multiply parentheses

6x-(2(x+5))-18-1=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

6x-(2x+10)-19=0

We get rid of parentheses

6x-2x-10-19=0

We add all the numbers together, and all the variables

4x-29=0

We move all terms containing x to the left, all other terms to the right

4x=29

x=29/4

x=7+1/4

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