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6(x-3)-3(x-2)=4(3-x)
We move all terms to the left:
6(x-3)-3(x-2)-(4(3-x))=0
We add all the numbers together, and all the variables
6(x-3)-3(x-2)-(4(-1x+3))=0
We multiply parentheses
6x-3x-(4(-1x+3))-18+6=0
We calculate terms in parentheses: -(4(-1x+3)), so:We add all the numbers together, and all the variables
4(-1x+3)
We multiply parentheses
-4x+12
Back to the equation:
-(-4x+12)
3x-(-4x+12)-12=0
We get rid of parentheses
3x+4x-12-12=0
We add all the numbers together, and all the variables
7x-24=0
We move all terms containing x to the left, all other terms to the right
7x=24
x=24/7
x=3+3/7
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