6(x-3)-4(x+1)=0

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Solution for 6(x-3)-4(x+1)=0 equation: 



6(x-3)-4(x+1)=0

We multiply parentheses

6x-4x-18-4=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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