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6(x-3)-5(4x+3)=x-33
We move all terms to the left:
6(x-3)-5(4x+3)-(x-33)=0
We multiply parentheses
6x-20x-(x-33)-18-15=0
We get rid of parentheses
6x-20x-x+33-18-15=0
We add all the numbers together, and all the variables
-15x=0
x=0/-15
x=0
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