6(x-3)/3=2(x+1)/5

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Solution for 6(x-3)/3=2(x+1)/5 equation:



6(x-3)/3=2(x+1)/5
We move all terms to the left:
6(x-3)/3-(2(x+1)/5)=0
We calculate fractions
6x/()+(-(2(x+1)*3)/()=0
We calculate terms in parentheses: +(-(2(x+1)*3)/(), so:
-(2(x+1)*3)/(
We multiply all the terms by the denominator
-(2(x+1)*3)
We calculate terms in parentheses: -(2(x+1)*3), so:
2(x+1)*3
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
We get rid of parentheses
-6x-6
Back to the equation:
+(-6x-6)
We get rid of parentheses
6x/()-6x-6=0
We multiply all the terms by the denominator
6x-6x*()-6*()=0
We add all the numbers together, and all the variables
6x-6x*()=0

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