6(x-3)/4=3(x+4)/9

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Solution for 6(x-3)/4=3(x+4)/9 equation: 



6(x-3)/4=3(x+4)/9

We move all terms to the left:

6(x-3)/4-(3(x+4)/9)=0

We calculate fractions


6x/()+(-(3(x+4)*4)/()=0



We calculate terms in parentheses: +(-(3(x+4)*4)/(), so:

-(3(x+4)*4)/(

We multiply all the terms by the denominator


-(3(x+4)*4)



We calculate terms in parentheses: -(3(x+4)*4), so:

3(x+4)*4

We multiply parentheses

12x+48

Back to the equation:

-(12x+48)



We get rid of parentheses

-12x-48

Back to the equation:

+(-12x-48)



We get rid of parentheses

6x/()-12x-48=0

We multiply all the terms by the denominator


6x-12x*()-48*()=0

We add all the numbers together, and all the variables

6x-12x*()=0

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