6(x-3)/9=(x+2)/8

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Solution for 6(x-3)/9=(x+2)/8 equation: 



6(x-3)/9=(x+2)/8

We move all terms to the left:

6(x-3)/9-((x+2)/8)=0

We calculate fractions


6x/()+(-((x+2)*9)/()=0



We calculate terms in parentheses: +(-((x+2)*9)/(), so:

-((x+2)*9)/(

We multiply all the terms by the denominator


-((x+2)*9)



We calculate terms in parentheses: -((x+2)*9), so:

(x+2)*9

We multiply parentheses

9x+18

Back to the equation:

-(9x+18)



We get rid of parentheses

-9x-18

Back to the equation:

+(-9x-18)



We get rid of parentheses

6x/()-9x-18=0

We multiply all the terms by the denominator


6x-9x*()-18*()=0

We add all the numbers together, and all the variables

6x-9x*()=0

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