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6(x-3)/9=2(x+2)/8
We move all terms to the left:
6(x-3)/9-(2(x+2)/8)=0
We calculate fractions
6x/()+(-(2(x+2)*9)/()=0
We calculate terms in parentheses: +(-(2(x+2)*9)/(), so:We get rid of parentheses
-(2(x+2)*9)/(
We multiply all the terms by the denominator
-(2(x+2)*9)
We calculate terms in parentheses: -(2(x+2)*9), so:We get rid of parentheses
2(x+2)*9
We multiply parentheses
18x+36
Back to the equation:
-(18x+36)
-18x-36
Back to the equation:
+(-18x-36)
6x/()-18x-36=0
We multiply all the terms by the denominator
6x-18x*()-36*()=0
We add all the numbers together, and all the variables
6x-18x*()=0
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