6(x-3)=-4(x+2)+48

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Solution for 6(x-3)=-4(x+2)+48 equation: 



6(x-3)=-4(x+2)+48

We move all terms to the left:

6(x-3)-(-4(x+2)+48)=0

We multiply parentheses

6x-(-4(x+2)+48)-18=0



We calculate terms in parentheses: -(-4(x+2)+48), so:

-4(x+2)+48

We multiply parentheses

-4x-8+48

We add all the numbers together, and all the variables

-4x+40

Back to the equation:

-(-4x+40)



We get rid of parentheses

6x+4x-40-18=0

We add all the numbers together, and all the variables

10x-58=0

We move all terms containing x to the left, all other terms to the right

10x=58

x=58/10

x=5+4/5

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