6(x-3)=-4(x+4)+42

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Solution for 6(x-3)=-4(x+4)+42 equation:



6(x-3)=-4(x+4)+42
We move all terms to the left:
6(x-3)-(-4(x+4)+42)=0
We multiply parentheses
6x-(-4(x+4)+42)-18=0
We calculate terms in parentheses: -(-4(x+4)+42), so:
-4(x+4)+42
We multiply parentheses
-4x-16+42
We add all the numbers together, and all the variables
-4x+26
Back to the equation:
-(-4x+26)
We get rid of parentheses
6x+4x-26-18=0
We add all the numbers together, and all the variables
10x-44=0
We move all terms containing x to the left, all other terms to the right
10x=44
x=44/10
x=4+2/5

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