6(x-3)=-x+2(x+6)

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Solution for 6(x-3)=-x+2(x+6) equation: 



6(x-3)=-x+2(x+6)

We move all terms to the left:

6(x-3)-(-x+2(x+6))=0

We multiply parentheses

6x-(-x+2(x+6))-18=0



We calculate terms in parentheses: -(-x+2(x+6)), so:

-x+2(x+6)

We add all the numbers together, and all the variables

-1x+2(x+6)

We multiply parentheses

-1x+2x+12

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

6x-x-12-18=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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