6(x-3)=10-2(3x-4)

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Solution for 6(x-3)=10-2(3x-4) equation: 



6(x-3)=10-2(3x-4)

We move all terms to the left:

6(x-3)-(10-2(3x-4))=0

We multiply parentheses

6x-(10-2(3x-4))-18=0



We calculate terms in parentheses: -(10-2(3x-4)), so:

10-2(3x-4)

determiningTheFunctionDomain
-2(3x-4)+10

We multiply parentheses

-6x+8+10

We add all the numbers together, and all the variables

-6x+18

Back to the equation:

-(-6x+18)



We get rid of parentheses

6x+6x-18-18=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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