6(x-3)=3(4+x)

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Solution for 6(x-3)=3(4+x) equation: 



6(x-3)=3(4+x)

We move all terms to the left:

6(x-3)-(3(4+x))=0

We add all the numbers together, and all the variables

6(x-3)-(3(x+4))=0

We multiply parentheses

6x-(3(x+4))-18=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

6x-3x-12-18=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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