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6(x-3)=3(4x+2)=
We move all terms to the left:
6(x-3)-(3(4x+2))=0
We multiply parentheses
6x-(3(4x+2))-18=0
We calculate terms in parentheses: -(3(4x+2)), so:We get rid of parentheses
3(4x+2)
We multiply parentheses
12x+6
Back to the equation:
-(12x+6)
6x-12x-6-18=0
We add all the numbers together, and all the variables
-6x-24=0
We move all terms containing x to the left, all other terms to the right
-6x=24
x=24/-6
x=-4
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