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6(x-3)=3(x+6)
We move all terms to the left:
6(x-3)-(3(x+6))=0
We multiply parentheses
6x-(3(x+6))-18=0
We calculate terms in parentheses: -(3(x+6)), so:We get rid of parentheses
3(x+6)
We multiply parentheses
3x+18
Back to the equation:
-(3x+18)
6x-3x-18-18=0
We add all the numbers together, and all the variables
3x-36=0
We move all terms containing x to the left, all other terms to the right
3x=36
x=36/3
x=12
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