6(x-3)=4(-x+1)

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Solution for 6(x-3)=4(-x+1) equation: 



6(x-3)=4(-x+1)

We move all terms to the left:

6(x-3)-(4(-x+1))=0

We add all the numbers together, and all the variables

6(x-3)-(4(-1x+1))=0

We multiply parentheses

6x-(4(-1x+1))-18=0



We calculate terms in parentheses: -(4(-1x+1)), so:

4(-1x+1)

We multiply parentheses

-4x+4

Back to the equation:

-(-4x+4)



We get rid of parentheses

6x+4x-4-18=0

We add all the numbers together, and all the variables

10x-22=0

We move all terms containing x to the left, all other terms to the right

10x=22

x=22/10

x=2+1/5

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