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6(x-3)=5(3x+2)
We move all terms to the left:
6(x-3)-(5(3x+2))=0
We multiply parentheses
6x-(5(3x+2))-18=0
We calculate terms in parentheses: -(5(3x+2)), so:We get rid of parentheses
5(3x+2)
We multiply parentheses
15x+10
Back to the equation:
-(15x+10)
6x-15x-10-18=0
We add all the numbers together, and all the variables
-9x-28=0
We move all terms containing x to the left, all other terms to the right
-9x=28
x=28/-9
x=-3+1/9
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