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6(x-3)=5-2(3x-4)
We move all terms to the left:
6(x-3)-(5-2(3x-4))=0
We multiply parentheses
6x-(5-2(3x-4))-18=0
We calculate terms in parentheses: -(5-2(3x-4)), so:We get rid of parentheses
5-2(3x-4)
determiningTheFunctionDomain -2(3x-4)+5
We multiply parentheses
-6x+8+5
We add all the numbers together, and all the variables
-6x+13
Back to the equation:
-(-6x+13)
6x+6x-13-18=0
We add all the numbers together, and all the variables
12x-31=0
We move all terms containing x to the left, all other terms to the right
12x=31
x=31/12
x=2+7/12
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