6(x-4)+12=6+3(x+4)

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Solution for 6(x-4)+12=6+3(x+4) equation: 



6(x-4)+12=6+3(x+4)

We move all terms to the left:

6(x-4)+12-(6+3(x+4))=0

We multiply parentheses

6x-(6+3(x+4))-24+12=0



We calculate terms in parentheses: -(6+3(x+4)), so:

6+3(x+4)

determiningTheFunctionDomain
3(x+4)+6

We multiply parentheses

3x+12+6

We add all the numbers together, and all the variables

3x+18

Back to the equation:

-(3x+18)



We add all the numbers together, and all the variables

6x-(3x+18)-12=0

We get rid of parentheses

6x-3x-18-12=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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