6(x-4)+3(x-1)-5(x+2)+3(8-x)=-3-x

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Solution for 6(x-4)+3(x-1)-5(x+2)+3(8-x)=-3-x equation: 



6(x-4)+3(x-1)-5(x+2)+3(8-x)=-3-x

We move all terms to the left:

6(x-4)+3(x-1)-5(x+2)+3(8-x)-(-3-x)=0

We add all the numbers together, and all the variables

6(x-4)+3(x-1)-5(x+2)+3(-1x+8)-(-1x-3)=0

We multiply parentheses

6x+3x-5x-3x-(-1x-3)-24-3-10+24=0

We get rid of parentheses

6x+3x-5x-3x+1x+3-24-3-10+24=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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