6(x-4)+3=2(x+7)

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Solution for 6(x-4)+3=2(x+7) equation: 



6(x-4)+3=2(x+7)

We move all terms to the left:

6(x-4)+3-(2(x+7))=0

We multiply parentheses

6x-(2(x+7))-24+3=0



We calculate terms in parentheses: -(2(x+7)), so:

2(x+7)

We multiply parentheses

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

6x-(2x+14)-21=0

We get rid of parentheses

6x-2x-14-21=0

We add all the numbers together, and all the variables

4x-35=0

We move all terms containing x to the left, all other terms to the right

4x=35

x=35/4

x=8+3/4

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