6(x-4)+7=2(x+4)

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Solution for 6(x-4)+7=2(x+4) equation: 



6(x-4)+7=2(x+4)

We move all terms to the left:

6(x-4)+7-(2(x+4))=0

We multiply parentheses

6x-(2(x+4))-24+7=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

6x-(2x+8)-17=0

We get rid of parentheses

6x-2x-8-17=0

We add all the numbers together, and all the variables

4x-25=0

We move all terms containing x to the left, all other terms to the right

4x=25

x=25/4

x=6+1/4

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