6(x-4)+7x=-5(x-8)+8

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Solution for 6(x-4)+7x=-5(x-8)+8 equation: 



6(x-4)+7x=-5(x-8)+8

We move all terms to the left:

6(x-4)+7x-(-5(x-8)+8)=0

We add all the numbers together, and all the variables

7x+6(x-4)-(-5(x-8)+8)=0

We multiply parentheses

7x+6x-(-5(x-8)+8)-24=0



We calculate terms in parentheses: -(-5(x-8)+8), so:

-5(x-8)+8

We multiply parentheses

-5x+40+8

We add all the numbers together, and all the variables

-5x+48

Back to the equation:

-(-5x+48)



We add all the numbers together, and all the variables

13x-(-5x+48)-24=0

We get rid of parentheses

13x+5x-48-24=0

We add all the numbers together, and all the variables

18x-72=0

We move all terms containing x to the left, all other terms to the right

18x=72

x=72/18

x=4

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