6(x-4)+x=7(x-5)+11

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Solution for 6(x-4)+x=7(x-5)+11 equation: 



6(x-4)+x=7(x-5)+11

We move all terms to the left:

6(x-4)+x-(7(x-5)+11)=0

We add all the numbers together, and all the variables

x+6(x-4)-(7(x-5)+11)=0

We multiply parentheses

x+6x-(7(x-5)+11)-24=0



We calculate terms in parentheses: -(7(x-5)+11), so:

7(x-5)+11

We multiply parentheses

7x-35+11

We add all the numbers together, and all the variables

7x-24

Back to the equation:

-(7x-24)



We add all the numbers together, and all the variables

7x-(7x-24)-24=0

We get rid of parentheses

7x-7x+24-24=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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