6(x-4)/12=6(x+1)/23

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Solution for 6(x-4)/12=6(x+1)/23 equation: 



6(x-4)/12=6(x+1)/23

We move all terms to the left:

6(x-4)/12-(6(x+1)/23)=0

We calculate fractions


6x/()+(-(6(x+1)*12)/()=0



We calculate terms in parentheses: +(-(6(x+1)*12)/(), so:

-(6(x+1)*12)/(

We multiply all the terms by the denominator


-(6(x+1)*12)



We calculate terms in parentheses: -(6(x+1)*12), so:

6(x+1)*12

We multiply parentheses

72x+72

Back to the equation:

-(72x+72)



We get rid of parentheses

-72x-72

Back to the equation:

+(-72x-72)



We get rid of parentheses

6x/()-72x-72=0

We multiply all the terms by the denominator


6x-72x*()-72*()=0

We add all the numbers together, and all the variables

6x-72x*()=0

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