6(x-4)/4=3(x+1)/7

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Solution for 6(x-4)/4=3(x+1)/7 equation: 



6(x-4)/4=3(x+1)/7

We move all terms to the left:

6(x-4)/4-(3(x+1)/7)=0

We calculate fractions


6x/()+(-(3(x+1)*4)/()=0



We calculate terms in parentheses: +(-(3(x+1)*4)/(), so:

-(3(x+1)*4)/(

We multiply all the terms by the denominator


-(3(x+1)*4)



We calculate terms in parentheses: -(3(x+1)*4), so:

3(x+1)*4

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

-12x-12

Back to the equation:

+(-12x-12)



We get rid of parentheses

6x/()-12x-12=0

We multiply all the terms by the denominator


6x-12x*()-12*()=0

We add all the numbers together, and all the variables

6x-12x*()=0

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