6(x-4)=2(x+20)

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Solution for 6(x-4)=2(x+20) equation: 



6(x-4)=2(x+20)

We move all terms to the left:

6(x-4)-(2(x+20))=0

We multiply parentheses

6x-(2(x+20))-24=0



We calculate terms in parentheses: -(2(x+20)), so:

2(x+20)

We multiply parentheses

2x+40

Back to the equation:

-(2x+40)



We get rid of parentheses

6x-2x-40-24=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16

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