6(x-5)+10=4(x+0)

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Solution for 6(x-5)+10=4(x+0) equation: 



6(x-5)+10=4(x+0)

We move all terms to the left:

6(x-5)+10-(4(x+0))=0

We add all the numbers together, and all the variables

6(x-5)-(4(+x))+10=0

We multiply parentheses

6x-(4(+x))-30+10=0



We calculate terms in parentheses: -(4(+x)), so:

4(+x)

We multiply parentheses

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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