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6(x-5)+12=x-(18-5x)
We move all terms to the left:
6(x-5)+12-(x-(18-5x))=0
We add all the numbers together, and all the variables
6(x-5)-(x-(-5x+18))+12=0
We multiply parentheses
6x-(x-(-5x+18))-30+12=0
We calculate terms in parentheses: -(x-(-5x+18)), so:We add all the numbers together, and all the variables
x-(-5x+18)
We get rid of parentheses
x+5x-18
We add all the numbers together, and all the variables
6x-18
Back to the equation:
-(6x-18)
6x-(6x-18)-18=0
We get rid of parentheses
6x-6x+18-18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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