6(x-5)+2=32

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Solution for 6(x-5)+2=32 equation: 



6(x-5)+2=32

We move all terms to the left:

6(x-5)+2-(32)=0

We add all the numbers together, and all the variables

6(x-5)-30=0

We multiply parentheses

6x-30-30=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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