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6(x-5)+3(x-4)=4(x+2)
We move all terms to the left:
6(x-5)+3(x-4)-(4(x+2))=0
We multiply parentheses
6x+3x-(4(x+2))-30-12=0
We calculate terms in parentheses: -(4(x+2)), so:We add all the numbers together, and all the variables
4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
9x-(4x+8)-42=0
We get rid of parentheses
9x-4x-8-42=0
We add all the numbers together, and all the variables
5x-50=0
We move all terms containing x to the left, all other terms to the right
5x=50
x=50/5
x=10
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