6(x-5)+4(x+3)=18

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Solution for 6(x-5)+4(x+3)=18 equation: 



6(x-5)+4(x+3)=18

We move all terms to the left:

6(x-5)+4(x+3)-(18)=0

We multiply parentheses

6x+4x-30+12-18=0

We add all the numbers together, and all the variables

10x-36=0

We move all terms containing x to the left, all other terms to the right

10x=36

x=36/10

x=3+3/5

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